RE: SLC/WK1: "Advanced Electrical Transformers and Power Factor"
A. You have determined step-up and step-down transformers based on voltage. Step up and step down can be determined by looking at the primary and secondary turns of the transformer. The turn ratio of your transformer is correct.
B. You have not written the names of some important parts of the transformer. Transformers don't identify different parts in the picture.
C. The electrical home appliances in our house are of low voltage, so the power supply is given to our house using a step-down transformer.
D. You have not calculated the transformer correctly for a 5000 KW electrical load. 6MVA transformer will be required based on the power factor. I hope you understand your mistake.
E. You did not mention the name of the transformer when looking at the nameplate of the transformer. The transformer was a step-down power transformer.
F. The HV and LV currents of your 2.5 MVA transformer are correct. The same current rating is on the name-plate of the above transformer.
G. The power company's electricity loss is known through the power factor. Improvement of power factor is done by using a power capacitor.
H. The trade name of transformer oil is pyranol. It will be true. I hope you understand your mistake.
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Comment/Recommendation
Thank you for reading Industrial Electrical Lessons and doing homework. You have wrongly rated the transformer for a 5000 kW electrical load. I think you misunderstood the question. It is very important to calculate such a transformer correctly. Good luck to you.
Scores
Sl. No | Score | Sl. No | Score |
---|---|---|---|
A | 1.5 | E | 0.4 |
B | 1 | F | 2.5 |
C | 0.5 | G | 0.4 |
D | 0 | H | 1.3 |
Total | 7.6 |
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